Find the Error: Solving Homework Problems

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Harmony
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Harmony said:
May I know which part of my solution went wrong? In the end the answer gives x/2 instead of 0.

Since [tex]y' (x)[/tex] contains only odd powers of x, the n=1 term does not vanish when you take the derivative of the series. Therefore,

[tex]y'' (x)= \sum_{n=1}^{\infty} \frac{(-1)^n (2n)(2n-1) x^{2n-2}}{4^n (n!)^2}[/tex]

The extra [tex]x/2[/tex] in your answer will be canceled by the [tex]n=1[/tex] term.