Find the final speed of a skier if he lands 145m down a 20 degree slope?

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SUMMARY

The final speed of a skier landing 145m down a 20-degree slope can be calculated using principles of energy conservation and kinematics. The skier starts with an initial speed of 4.00 m/s and descends from a height of 120m to 3.00m above the snow, resulting in a height difference of 117m. With no friction on the ramp and accounting for a 50% loss in kinetic energy due to air resistance, the final speed can be determined through the equation KE = (1/2)mvf^2 - (1/2)mvi^2.

PREREQUISITES
  • Understanding of gravitational potential energy (U = mgy)
  • Knowledge of kinetic energy equations (KE = (1/2)mv^2)
  • Basic principles of energy conservation in physics
  • Familiarity with trigonometric functions related to slopes
NEXT STEPS
  • Calculate the potential energy lost by the skier during the descent
  • Determine the final speed using the modified kinetic energy equation
  • Explore the effects of air resistance on kinetic energy in similar scenarios
  • Investigate the application of energy conservation in other sports physics problems
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of motion in sports, particularly in scenarios involving slopes and energy loss due to air resistance.

woopycushion
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Homework Statement


A skier leaves the starting gate at the top of a ski jump with an initial speed of 4.00 m/s. The starting position is 120m higher than the end of the ramp, which is 3.00m above the snow. Find the final speed of the skier if he lands 145m down the 20 degree slope. Assume there is no friction on the ramp, but air resistance causes a 50% loss in the final kinetic energy. The GPS reading of the elevation of the skier is 4212m at the top of the jump and 4039m at the landing point.


Homework Equations



U(x)=mgy
KE = (1/2)mvf^2 - (1/2)mvi(2)
vi = 4.00 m/s

The Attempt at a Solution

 
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That's a good start - a sketch of what happens will also help you.
If you make an attempt at the solution I will be in a position to help you ;)
 

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