Find the height of each right cylinder

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SUMMARY

The discussion focuses on calculating the height of concrete right cylinders required for hurricane protection, given a radius of 4 inches and a weight of 1200 pounds per cylinder. The correct approach involves using the formula for volume, V = πr²h, and understanding the relationship between weight, density, and volume. The density of concrete is specified as 150 pounds per cubic foot, leading to the conclusion that the height of each cylinder should be approximately 23.87 inches or 1 foot 11.87 inches when calculated correctly.

PREREQUISITES
  • Understanding of volume calculation for right cylinders
  • Knowledge of density and its application in weight calculations
  • Familiarity with unit conversion (inches to feet)
  • Basic algebra for solving equations
NEXT STEPS
  • Learn about unit conversion techniques in engineering calculations
  • Study the properties of concrete and its density variations
  • Explore advanced volume calculations for different geometric shapes
  • Investigate the implications of weight distribution in structural engineering
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Students in engineering or architecture, construction professionals, and anyone involved in structural design and material calculations for safety and durability.

Meadow Delorto
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Homework Statement


I have to construct 8 concrete right cylinders for hurricane protection on windows, but I need to know the height to fit the given criteria. Each has a 4 inch radius and each weighs 1200 pounds. Concrete weighs 150 pounds per cubic foot.

V= volume of right cylinder
r=radius
h= height of right cylinder

Homework Equations


V=pi*r^2*h

The Attempt at a Solution


V=pi*r^2*h
1200 lbs= pi*16*h
h=23.8732 inches (1’11.87”).

I just don’t know where the weight of concrete, 150 pounds per cubic foot, comes into play. Thank you very much.
 
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:welcome:You need to work in feet, not inches, and the equation you are missing is ## W=\delta \, V ##, where ## \delta ## is the density in pounds per cubic foot. When you compute the volume, the radius ## r ## needs to be converted to "x" feet. The answer you get for height ## h ## will be in feet.
 
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In your statement, you set V=1200 pounds. That is not right; ##V=\frac{weight}{density}##. The density is what give is 150 pounds per cubic foot.
 
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Charles Link said:
:welcome:You need to work in feet, not inches, and the equation you are missing is ## W=\delta \, V ##, where ## \delta ## is the density in pounds per cubic foot. When you compute the volume, the radius ## r ## needs to be converted to "x" feet. The answer you get for height ## h ## will be in feet.
Would I be correct if I said it would have to be 22.96 feet?
 
Meadow Delorto said:

Homework Statement


I have to construct 8 concrete right cylinders for hurricane protection on windows, but I need to know the height to fit the given criteria. Each has a 4 inch radius and each weighs 1200 pounds. Concrete weighs 150 pounds per cubic foot.

V= volume of right cylinder
r=radius
h= height of right cylinder

Homework Equations


V=pi*r^2*h

The Attempt at a Solution


V=pi*r^2*h
1200 lbs= pi*16*h
h=23.8732 inches (1’11.87”).

I just don’t know where the weight of concrete, 150 pounds per cubic foot, comes into play. Thank you very much.

If the final object weighs 1200 lb and concrete weighs 150 lb/cu.ft., how many cubic feet of concrete does the object consist of? So, what is the object's volume, in cubic feet?
 
Last edited:
You have the volume formula, and you know how much concrete and you have the density. So?

Convert 1200 pounds into the quantity in cubic feet.
Now use your volume formula to calculate the unknown height.
 

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