Find the length of the vector x (write sqrt(#)

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Homework Help Overview

The discussion revolves around two problems involving vector analysis, specifically focusing on the properties of vectors, including orthogonality and the calculation of vector length and unit vectors.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the orthogonality of vectors x, y, and z, using dot products to evaluate their relationships. They also explore the calculation of the length of vector x and the derivation of its unit vector, with some questioning the accuracy of the unit vector calculation.

Discussion Status

Participants have engaged in verifying calculations and clarifying concepts related to vector properties. There is acknowledgment of potential errors in the unit vector calculation, and some participants are prompted to recheck their work.

Contextual Notes

Participants are working within the constraints of homework rules, which may limit the extent of guidance provided. There is an emphasis on ensuring accuracy in mathematical expressions and definitions.

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I am working on 2 problems and wanted to know your thoughts on them:

Problem 1
Given the vectors x = <3,2,-4>, y = <-3/2,1,-2>, and z = <0,2,1>, select all statements below that apply.
A.
the vectors x and y are orthogonal.
B.
the vectors x and y are in opposite directions.
C.
the vectors x and z are orthogonal
D.
the vectors x and z are in opposite directions


2 Vectors are orthogonal if their dot product is 0.
2 vectors are orthogonal is the angle between them is 180.

To determine the angle between 2 vectors we can use the equation Cos ⊖= The dot product of the 2 vectors/ Distance of vector1 * distance of vector 2


A.
the vectors x and y are orthogonal.
The dot product of x and y is ( 3* -3/2 , 2*1, -4*-2) = (-9/2 + 2 + 8) = 11/2. hence x and y are not orthogonal

B.
the vectors x and y are in opposite directions.

Cos ⊖= 11/2 / (sqrt ( 29)* (sqrt(29)/ 2)) = 11/2 / 29/2 = 11/29
Cos ⊖ = 11/29 = approx 67.71 degrees. x and y are not in opposite directions.

C.
the vectors x and z are orthogonal
The dot product of x and z is ( 3* 0 , 2*2 , -4*-1) = (0 + 4 - 4). x and z are orthogonal.


D.
the vectors x and z are in opposite directions

Cos ⊖= 0 = 90 degrees. This confirms our answer in part C that x and z are orthogonal and create a right angle. they are not in opposite directions.



Problem 2
Given the vector x = <3,2,-4>,

1. find the length of the vector x (write sqrt(#) for square root to write your answer exactly).

2. find the unit vector in the same direction as x. (Write your answer exactly using the form <v1,v2,v3,...> , rationalize all denominators)

1) The length of a vector is the square root of the sum of squares. The length is sqrt ( 3^2 + 2^2 +(-4)^2 = sqrt ( 29)

2) The unit vector in the same direction of x is given by x/ length of x. We have ( 3, 2, -4) / sqrt(29) from part A. So we have ( 3*sqrt(29)/ 29 , 2*sqrt(29), -4*sqrt(29)/ 29)
 
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Your calculations look fine to me. I didn't double-check anything with a calculator, but the answers I found agree with yours.

On your last problem, your unit vector is incorrect, possibly you forgot to type in a number.

Also, this statement is incorrect: "2 vectors are orthogonal is the angle between them is 180."

And, when calculating the dot product of two vectors and writing the multiplication of each term, I would be careful not to write it as a vector.

Example: It is not really a good habit to write: (a,b,c) · (x,y,z) = (ax,by,cz) = ax + by + cz. It can be simply written: (a,b,c) · (x,y,z) = ax + by + cz.
 
Last edited:
Thanks

did you mean ( 3*sqrt(29)/ 29 , 2*sqrt(29), -4*sqrt(29)/ 29) is incorrect? I will re check that problem if so
 
Yes, it is, due to a minor error.
 
youre right
it should be ( 3*sqrt(29)/ 29 , 2*sqrt(29)/ 29, -4*sqrt(29)/ 29)
 

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