# Find the limit of ln (sinx) as x approaches pi

1. Jan 27, 2013

### essedbl

I need to find the limit of. Ln (sinx) as x approaches pi-, that is, as x approaches pi from the left.

I thought I should use the squeeze theorem, but I am not sure how to apply it. My teacher is not requiring us to use the delta/Epsilon method, so I am sure it is a squeeze method. But how do I set it up?

I tried -1 < sinx < 1,
Thus ln (-1) < ln (sinx) < ln (1)

2. Jan 27, 2013

### jbunniii

What can you say about $\sin(x)$ as $x \rightarrow \pi^-$? Is it positive or negative? What value does it approach?

3. Jan 27, 2013

### Sayajin

As x aproaches pi from the left your sine function aproaches 0. This means this is equivalent of finding the limit as the thing inside the natural log aproaches 0. Its very easy limit.

Last edited: Jan 27, 2013
4. Jan 27, 2013

### essedbl

Oh. So this isnt squeeze action... I just find the limit of ln as sinx approaches zero. Hmm... I would need to graph that. But that should be simple enough. Tjanks guys

5. Jan 27, 2013

### Staff: Mentor

Good idea. Remember that x is approaching π from the left, which says something about how sin(x) is approaching zero, and finally, what ln(sin(x)) is doing.