Find the magnitude of the net force acting on this object

Click For Summary

Homework Help Overview

The problem involves determining the magnitude of the net force acting on a 3.00 kg object moving in a plane, with its position described by equations for x and y coordinates as functions of time. The specific inquiry is focused on the net force at a given time, t = 2.00 seconds.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the possibility of substituting time into the position equations to find displacement and question how to sum forces after drawing a free body diagram. Some suggest using the relationship F = ma and finding acceleration from the position equations. Others propose taking derivatives of the position functions to obtain velocity and then acceleration.

Discussion Status

The discussion is active, with participants exploring different methods to find acceleration and subsequently the net force. There is no explicit consensus, but some guidance has been offered regarding the use of derivatives to find acceleration from position functions.

Contextual Notes

Participants are navigating the problem without a free body diagram and are considering the implications of having separate accelerations in the x and y directions. There is an emphasis on understanding the relationships between position, velocity, and acceleration in the context of force calculation.

student 1
Messages
76
Reaction score
0

Homework Statement


A 3.00 Kg object is moving in a plane, with its x and y coordinates given by x=5t^2-1 and y=3t^3+2, where x and y in meters and t in seconds. Find the magnitude of the net force acting on this object at t=2.00 secs.


Homework Equations





The Attempt at a Solution


Would you just substitute T in the equations to find the displacement of the object and then sum all the forces? I do not know how to sum the forces after I get the free body diagram drawn. Any tips??
 
Physics news on Phys.org
You do not need a free body diagram. F = ma. You want F, you know m, can you find a?
 
Alright, so you use the distance it traveled to find the acceleration correct? Then as soon as you have that all you would need is Mass times acceleration to get force, but you have two separate acceleration one in the x and one in the y correct?
 
Since you have the position formulas for x and y could you do the derivative of that to get your velocity and then derivative of that to get your acceleration? Then you would have it? Or am I off base?
 
student 1 said:
Since you have the position formulas for x and y could you do the derivative of that to get your velocity and then derivative of that to get your acceleration? Then you would have it? Or am I off base?

Yes, that is how you should approach the problem.
 

Similar threads

Replies
8
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
4K