A light rope fixed at one end to the wooden clamp on the ground passes over a tree branch and hangs on the other side. It makes an angle 30° with the ground. A man weighing 60 kg wants to climb up the rope. The wooden clamp can come out of the ground if an upward force greater than 360N is applied to it. Find the maximum acceleration in the upward direction with which the man can climb safely. Neglect friction at the tree branch. Take g ≈ 10m /s^2. Let t be tension in rope. Then upward force on the clamp is tsin30°≈t/2≈360N. T≈720N Let a be acceleration of man in upward direction then, T-600N≈60 kg . a Therefore maximun acceleration of the man is a≈ (720-600)N/60 kg. ≈ 2m/s^2. Now my question is if we draw the tree body diagram of the wooden clamp we should include the normal contact force by the rope and the ground.Therefore upward force on the clamp is the resultant of the of the normal contact force by the rope and the tension in it. Why then we only consider the tension in the rope as the only upward force.