Find the Range of Forces for Which Block Does Not Slide

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Homework Help Overview

The problem involves a block on a wedge, where the goal is to determine the range of horizontal forces for which the block remains stationary relative to the wedge. The scenario includes a mass of the block, the wedge, an angle of inclination, and a coefficient of static friction.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of free-body diagrams and the summation of forces acting on the block. Questions arise regarding the normal force and its relationship to the forces acting on the block and wedge.

Discussion Status

Participants are actively engaging with the problem, exploring different components of the forces involved. Guidance has been offered regarding the normal force and its role in the system, but no consensus or resolution has been reached yet.

Contextual Notes

There is uncertainty regarding the calculation of the normal force and how the applied force on the wedge influences it. The discussion is framed within the constraints of static friction and the conditions for the block to remain stationary.

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Homework Statement



A block of mass .5 kg is on a wedge of mass 2.00 kg. The inclined surface makes an angle of 40 degrees with the horizontal. The wedge is subjected to a horizontqal force F and slides on a frictionless horizontal surface. The coefficient of static friction between the block and the wedge is .6 Find the range of values of F for which the block does not slide.
 
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... did you start by making a free-body diagram?

Try that see if you can sum forces...
 
Wesleytf said:
... did you start by making a free-body diagram?

Try that see if you can sum forces...

I've tried with the axes being x down the incline and y perpendicular to the incline.

sum of the forces in the x for the block is zero. The forces down the incline is gravity, which is mgsin 40 and coefficient of static friction*normal. I'm not sure what the normal is, and how the force applied to the wedge affects it.
 
The normal force is what keeps the block on the wedge. The component of g that is along your new y-axis will be equal in magnitude to the normal force. does that help?
 

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