Find the relation between x,y and z

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The discussion centers on finding the relationship between coplanar points A, B, C, and D, represented by their coordinates. The equation a(2-x, 2, 2) + b(2, 2-y, 2) + c(2, 2, 2-z) = (1, 1, 1) is analyzed, leading to the conclusion that ax = by = cz = k. However, the derived relationship 1/x + 1/y + 1/z = 1 does not hold in the specific case presented. An additional constraint regarding the collinearity of the vectors is highlighted, indicating that arbitrary coefficients a, b, and c can only generate vectors within the desired plane if the vectors are not collinear. The importance of this constraint is emphasized for achieving the correct relationship.
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Homework Statement


The coplanar points A,B,C,D are (2-x, 2,2); (2,2-y,2); (2,2,2-z): (1,1,1)

Homework Equations



The Attempt at a Solution


a(2-x, 2,2) + b(2,2-y,2) + c(2,2,2-z) = (1,1,1)

Equating respective components

ax=by=cz=k

The answer is 1/x + 1/y + 1/z = 1 but in my case it does not satisfy this.
 
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utkarshakash said:

Homework Statement


The coplanar points A,B,C,D are (2-x, 2,2); (2,2-y,2); (2,2,2-z): (1,1,1)

Homework Equations



The Attempt at a Solution


a(2-x, 2,2) + b(2,2-y,2) + c(2,2,2-z) = (1,1,1)

Equating respective components

ax=by=cz=k

The answer is 1/x + 1/y + 1/z = 1 but in my case it does not satisfy this.

Look here: http://mathworld.wolfram.com/Coplanar.html
 
utkarshakash said:
a(2-x, 2,2) + b(2,2-y,2) + c(2,2,2-z) = (1,1,1)
True, but there is another constraint on a, b, c. If the three vectors on the left are not collinear then with arbitrary a, b and c you could generate any vector in the space, not just those in the desired plane.
If you bring in that extra constraint, the result does follow.
 

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