1. The problem statement, all variables and given/known data To measure the inductance and resistance of a real inductor, a physicist first connects the inductor to a 3V battery. At these conditions, the final, steady, current is 24 A. Then the physicist suddenly short-circuits the inductor with a thick (resistance-less) wire place across its terminals. The current then decreases from 24 A to 12 A in 0.22 s. Find the resistance and the inductance. 2. Relevant equations ε = 3V I1 = 24A I2 = 12A t = 0.22s L = (εL X dt) / DI R = L / time constant 3. The attempt at a solution For L: (3v X .22s) / 12A = 0.0275H For R: 0.0275H / 0.22s = 0.125Ω Would that be right? It seems like what I did is so simple for a physics assignment, I get suspicious of it..