Find the solution to the initial value problem

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The discussion focuses on solving the initial value problem dy/dx - y = e^3x with the condition y(0) = 3. The participant correctly identifies p(x) as -1 and calculates the integrating factor I(x) = e^-x. However, their solution is incorrect as it does not satisfy the initial condition. A mistake is noted in the second to last line of their working, which needs correction for the solution to be valid. The thread emphasizes the importance of ensuring that the final answer meets the initial value requirement.
mad_monkey_j
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Homework Statement


Find the solution to the initial value problem
dy/dx - y = e^3x
y(0) = 3

Homework Equations


e^∫p(x)

The Attempt at a Solution


Do I treat p(x) = -1?
I(x) = e^∫-1 = e^-x
e^-x(dy/dx) - ye^-x = e^3x . e^-x
e^-x(dy/dx) - e^-x . y = e^2x
e^-x . y = ∫e^2x
y = (2e^2x + c)/(e^-x)
y = C+2e^3x?
 
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mad_monkey_j said:

Homework Statement


Find the solution to the initial value problem
dy/dx - y = e^3x
y(0) = 3

Homework Equations


e^∫p(x)

The Attempt at a Solution


Do I treat p(x) = -1?
I(x) = e^∫-1 = e^-x
e^-x(dy/dx) - ye^-x = e^3x . e^-x
e^-x(dy/dx) - e^-x . y = e^2x
e^-x . y = ∫e^2x
y = (2e^2x + c)/(e^-x)
y = C+2e^3x?
Yes, in this case p(x)=-1. However, you're answer isn't correct as it doesn't satisfy the initial value problem. You have made a little slit in the second to last line of your working.
 
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