- #1

quatrarot

- 2

- 0

This is a problem I have tried numerous times but keep coming up with different solutions, any help would be greatly appreciated.

## The Attempt at a Solution

let y = the helicopter's altitude

let x = car's distance to directly below the helicopter.

let h = the distance in miles between the helicopter and the car

let dh/dt = 190 miles/hour

150 miles/hour + dx/dt = horizontal component of car and helicopter.

then dx/dt is what we're looking for - the car's speed with respect to the ground.

y² + x² = h²

d(y²)/dt + d(x²)/dt = d(h²)/dt

dy/dt d(.5)²/dt + 150 + 2x dx/dt = d(1²)/dt 190 miles/hour = 0

2x dx/dt = 0 - 150 = -150miles/hour

x = √(1² - (.5)²) = √3/2

2(√3/2) dx/dt = -150 m/h

dx/dt = -150/√3 miles/hour

dx/dt = -86.60254 miles/hour