Find the taylor series of ln(1+x)

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Homework Help Overview

The problem involves finding the Taylor series expansion of the function ln(1+x) centered at zero. Participants are exploring the derivatives of the function to derive the series.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to compute the derivatives of ln(1+x) and expresses confusion regarding the coefficients in the Taylor series. Some participants encourage identifying a pattern in the coefficients and suggest developing a general term for the series.

Discussion Status

The discussion is active, with participants providing guidance on recognizing patterns in the derivatives. There is acknowledgment of the original poster's confusion, but no explicit consensus has been reached regarding the general term for the series.

Contextual Notes

Participants are considering the implications of the coefficients derived from the derivatives and questioning their understanding of the pattern, particularly with respect to factorial relationships.

vande060
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Homework Statement


find the taylor series of ln(1+x) centered at zero



Homework Equations



from 0 to infinity ∑ cn(x-a)n

cn = f(n)(a)/n!



The Attempt at a Solution



f(x) = ln(1+x)
f'(x) = 1/(1+x)
f''(x) = -1/(1+x)2
f'''(x) = 2/(1+x)3
f''''(x) = -6/(1+x)4


f(0) = 0
f'(0) = 1
f''(0) = -1
f'''(0) = 2
f''''(0) = -6

^ I feel like there is a mistake somewhere in the drivative, because one i set out the taylor series, it doesn't make much sense to me

0 + x/1! -x2/2! +2x3/3! -6x4/4!
 
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There's no mistake. Can you see a pattern? Can you find the general equation for the nth term in the expansion?
 
ideasrule said:
There's no mistake. Can you see a pattern? Can you find the general equation for the nth term in the expansion?

I tried to develop an nth term, but the 2 and 6 are messing me up, that why I thought it was wrong.

general term xn(-1)n+1/n! starting at n=1

It should resemble something like that, but I am not too sure, again I cannot figure out how to develop a general term that will explain the 2 and 6
 
Note that 2=2*1 and 6=3*2*1. I bet the next coefficient will be 24=4*3*2*1 (check this!)
 
2=2!

6=3!

Look at the next couple of derivatives of f if you need to.
 
okay I got it thanks
 

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