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Find the threshold frequency for a calcium

1. Homework Statement

This is a pretty simple problem... Yet I got the wrong answer.. Hmm...

"Find the threshold frequency for a calcium surface whose work function is 3.33eV"

W=3.33eV = 3.33eV * 1.6x10^-19 J = 5.33x10^19 J
f = ?
h=6.63x10^-34 J*S

2. Homework Equations

f=W/h

3. The Attempt at a Solution

f=(3.33eV)(1.6x10^-19 J) / (6.63x10^-34 J*S) = 8.04x10^14 Hz <- My answer


The answer in book is 5.02 x10^14 Hz.

Can anyone tell me what i'm doing wrong?
 
turns out the book was wrong... my answer was right. yah...
 

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