- #1

Kajan thana

- 151

- 18

- Homework Statement
- Find the specific heat capacity (Cp) with the given variables:

State:1.... p= 15 bars, Temperature: 600K,

State 2.... p= 1 bar, Temperature : 200, Enthalphy: -2000

This is an isentropic expansion.

- Relevant Equations
- Q-W=Cv(t2 -t2)

Cp/Cv= gamma

change in enthalphy = Cp * delta Temperature

I have managed to find the gamma value using the following equation: (T

Can someone help me with this question please?

I assume we have to find the enthalpy at state 1 to do that question.

_{2}/T_{1})= (P_{2}/P_{1})^{(gamma-1/gamma}. This will give me the answer of 1.29 SF. After this step, I am clueless.Can someone help me with this question please?

I assume we have to find the enthalpy at state 1 to do that question.