1. The problem statement, all variables and given/known data at t=0 switch S is closed. Just after the switch is closed what are i1, i2, the potential difference across V2 across resistor 2, and Vl across the inductor? A long time after the switch is closed, what are i1, i2, V2, and Vl? Emf = 12V, R1= 15 ohms, R2 = 25 ohms, and L = 5.0 H Now switch S is opened at t'=0. Just after the switch is opened, what are i1, i2, V2, and Vl? 2. Relevant equations V=iR Vl= -Ldi/dt 3. The attempt at a solution So just after t=0 no current passes through the inductor, so the Vl=12V and V2=0V. Using ohms law, the current in Resistor 1 is i=V/R => i1=0.8A A long time after the switch is closed the inductor now acts like a wire, and R1 & R2 are in paralell, therefore, i1=0.8 A and i2=0.48 A V2= 12V and Vl= 0V. When the switch is opened at t'=0 R1 & R2 are now in series with the inductor. So i1=i2 => i=V/(R1+R2)= 0.3A. The voltage on the inductor will be 12V to oppose the change in magnetic flux of the circuit. And V2=iR2=7.5V. So I am pretty positive about the first two parts of this question. It is really the opening of the switch at t'=0 that I am stuck on. Am I right to say that the Voltage through the inductor is 12V?