- #1

thomasrules

- 243

- 0

I found the first equation which is [tex]y=12x-16[/tex] by finding the derivative of [tex]y=x^3[/tex] which is [tex]y=3x^2[/tex].

I then plugged in [tex](2,8)[/tex] into [tex]y=mx+b[/tex] along with the slope of [tex]12[/tex].

But how can there be more than one slope at a single point? I don't get it