Find [v]s with Basis S={t+1,t-1} in P_1: v=5t-2"

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Homework Help Overview

The discussion revolves around finding the representation of the polynomial v=5t-2 in terms of the basis S={t+1,t-1} within the vector space P_1, which consists of polynomials of degree ≤1.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the representation of the polynomial using the basis, with some attempting to express v as a linear combination of the basis elements. Questions arise regarding the notation used for the representation and the correctness of the proposed coefficients.

Discussion Status

There are multiple attempts to express the polynomial in terms of the basis, with some participants providing their reasoning and others questioning the notation and correctness of the results. Guidance is offered regarding the need to show attempts before receiving help.

Contextual Notes

One participant mentions using Microsoft Word for formatting, which raises questions about accessibility for others who may not use the same software. This highlights a potential constraint in sharing solutions or representations effectively.

hadizainud
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Homework Statement



Let v=5t-2,S={v_1,v_2 }={t+1,t-1} is a basis of P_1 where P_1 is a vector space of all polynomials of degree ≤1. What is [v]s? Let v=5t-2,S={v_1,v_2 }={t+1,t-1} is a basis of P_1 where P_1 is a vector space of all polynomials of degree ≤1. What is [v]s?

2. The attempt at a solution
I need your help to provide me the correct way of putting the answers together, like the one in the answer scheme. Thanks in advance!
 
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v=[5t-2]=a[t+1]+b[t-1]

(1st) at+bt=5t
(2nd) a-b=-2
v=3⁄2 v_1+7⁄2 v_2
[v]_s=[■(3⁄2@7⁄2)]
is this correct?
 
hadizainud said:
v=[5t-2]=a[t+1]+b[t-1]

(1st) at+bt=5t
(2nd) a-b=-2
v=3⁄2 v_1+7⁄2 v_2
Looks good. I'm not exactly sure what the following notation means, though:
[v]_s=[■(3⁄2@7⁄2)]
is this correct?
 
Last edited:
What about those of us who do not use "Microsoft Word Office"?
 

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