Find volume of solid rotated about X axis Washer method

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Homework Help Overview

The discussion revolves around finding the volume of a solid of revolution using the washer method, specifically for the function y = x^2 + 1 over the interval [0, 1]. Participants are exploring the appropriate application of the integral formula for volume.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to square the function f(x) in the volume formula and question how to properly integrate the squared function. There are attempts to clarify the integration process and the correct application of the formula.

Discussion Status

The discussion is active with participants providing guidance on the integration process. Some have suggested multiplying out the squared function before integrating, while others are seeking clarification on the steps involved in taking the antiderivative.

Contextual Notes

There is some confusion regarding the integration of the squared function and the proper application of the volume formula. Participants are also addressing issues related to notation and the steps necessary to arrive at the solution.

2.7taudi
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Homework Statement



y=x^2+1
X in (0,1)

Homework Equations


formula needed
integral (PI [f(x)]^2 DX

in the F(x) just plug in the equation right?

The Attempt at a Solution


took anti deritive of the original problem and came out with

PI[1/3x^3+X]^2
my answer is 5.58

am i on the right track?

im confused on the squared part. Do i take the Anti deritive of the squared or only the thing inside the brackets?
 
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Right, you plug f(x) into the formula, but that ^2 means you square f(x), so [f(x)]^2 = (x^2 + 1)^2. That's what you actually want to integrate.
 
Bohrok said:
Right, you plug f(x) into the formula, but that ^2 means you square f(x), so [f(x)]^2 = (x^2 + 1)^2. That's what you actually want to integrate.

So how do i take the Anti deritive of that?

is it 1/3(x^2+1)^3*(1/3x^3+X)^2? I am going blank lol should there be a ^2 at the end of that?
 
Last edited:
That wouldn't be the way to integrate it

Easiest way would probably be to multiply it out,
(x2+1)2 = (x2+1)(x2+1) = ...
then integrate each term.
 
Bohrok said:
That wouldn't be the way to integrate it

Easiest way would probably be to multiply it out,
(x2+1)2 = (x2+1)(x2+1) = ...
then integrate each term.

Got it!

does this look right? excuse my chicken scratch handwriting.
 

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Yep, that's it!
 

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