Find Wavelength Homework: Solve with Plank's Constant

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Homework Help Overview

The discussion revolves around calculating the wavelength using Planck's constant in the context of a physics problem involving particle motion. The original poster attempts to apply the formula for wavelength but expresses uncertainty regarding their calculations and the expected answer.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of using a speed expressed as a fraction of the speed of light and question the accuracy of the original poster's calculations. There is a focus on verifying the speed used in the calculations and its conversion.

Discussion Status

The discussion is active, with participants providing clarifications regarding the interpretation of speed and its impact on the calculations. Some guidance has been offered regarding the correct speed to use, but no consensus on the final answer has been reached.

Contextual Notes

There is a noted confusion regarding the conversion of speed and the units used in the calculations. The original poster's approach is based on a specific interpretation of the problem statement, which may be contributing to the discrepancies in their results.

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Homework Statement


https://imgur.com/a/9UhMA

Homework Equations


Wavelength = planks constant/ mass*velocity

The Attempt at a Solution



(6.626*10^-34)/((9.11*10^-31)(.01*10^8)) = .728nm

which is an option but they have .243nm as the answer and I don't know where I did it wrong or what I needed to convert.
 
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What does the speed 0.01c mean to you?
 
Noreturn said:
.728nm
which is an option
Look again.
 
OH didn't even notice that it's a weird unit on the .728.

So .01 means it's going 1% the speed of light.
 
Noreturn said:
So .01 means it's going 1% the speed of light.

Yes
 
So where did I do the math wrong?
 
Noreturn said:
So where did I do the math wrong?

The speed of light is 3*10^8 m/s

What is 1% of that?

Is that the speed you used in your calculation?
 
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Likes   Reactions: Delta2
Oh perfect, thank you I don't know how I didn't catch that.
 

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