MHB Find Where Two Tangent Lines Intersect on a Circle | Math Help

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To find the intersection of two tangent lines on a circle, position the circle's center at the origin and align the tangent points with the same x-coordinate, one in the first quadrant and one in the fourth. The relationship between the radius (r), the length of the tangent line (ℓ), and the distance (d) can be expressed using the equation r² + ℓ² = d². By applying the distance formula and the equation of the circle, the problem simplifies to a solvable equation. Ultimately, the distance d can be calculated as d = r²/x, where x is the x-coordinate of the tangent points.
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Here is the question:

How can i find where two tangent lines intersect on a circle?

I need math help tonight. Is there a process i need to follow to find out where the lines meet?

I have posted a link there to this topic so the OP can see my work.
 
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Hello Getty,

We can greatly simplify this problem, if we orient the circle's center at the origin of our coordinate system, and rotate the circle such that the two tangent points have the same $x$-coordinate (where $0<x<r$), one point in the first quadrant, and one in the fourth quadrant.

Please refer to the following diagram:

View attachment 1164

Because $r$ and $\ell$ are perpendicular, we may state:

$$r^2+\ell^2=d^2$$

Using the distance formula, we find:

$$\ell^2=(x-d)^2+y^2$$

and from the equation of the circle, we have:

$$y^2=r^2-x^2$$

Hence, we may now write:

$$r^2+(x-d)^2+r^2-x^2=d^2$$

$$2r^2+x^2-2xd+d^2-x^2=d^2$$

$$r^2-xd=0$$

$$d=\frac{r^2}{x}$$
 

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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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