MHB Find Where Two Tangent Lines Intersect on a Circle | Math Help

MarkFL
Gold Member
MHB
Messages
13,284
Reaction score
12
Here is the question:

How can i find where two tangent lines intersect on a circle?

I need math help tonight. Is there a process i need to follow to find out where the lines meet?

I have posted a link there to this topic so the OP can see my work.
 
Mathematics news on Phys.org
Hello Getty,

We can greatly simplify this problem, if we orient the circle's center at the origin of our coordinate system, and rotate the circle such that the two tangent points have the same $x$-coordinate (where $0<x<r$), one point in the first quadrant, and one in the fourth quadrant.

Please refer to the following diagram:

View attachment 1164

Because $r$ and $\ell$ are perpendicular, we may state:

$$r^2+\ell^2=d^2$$

Using the distance formula, we find:

$$\ell^2=(x-d)^2+y^2$$

and from the equation of the circle, we have:

$$y^2=r^2-x^2$$

Hence, we may now write:

$$r^2+(x-d)^2+r^2-x^2=d^2$$

$$2r^2+x^2-2xd+d^2-x^2=d^2$$

$$r^2-xd=0$$

$$d=\frac{r^2}{x}$$
 

Attachments

  • getty.jpg
    getty.jpg
    8.6 KB · Views: 87
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.

Similar threads

Replies
2
Views
2K
Replies
2
Views
2K
Replies
59
Views
1K
Replies
4
Views
2K
Replies
4
Views
2K
Replies
2
Views
1K
Back
Top