Find Work Done on Homework Problem Involving Constant Force & Vector of PQ

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Homework Help Overview

The problem involves calculating the work done by a constant force as it acts on a point moving along a line segment defined by two points, P and Q. The force is given as a vector, and the task requires understanding the relationship between force, displacement, and work in a vector context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the components of vectors and the dot product as they relate to calculating work. There are attempts to clarify how to find the vector representing the displacement from P to Q, and questions arise about the correct application of these concepts.

Discussion Status

Some participants have shared their attempts at solving the problem, with varying results. There is a mix of understanding and confusion regarding the application of vector operations and the concept of work. Guidance has been offered on terminology and the correct approach to vector subtraction and dot product calculations.

Contextual Notes

Participants note that the instructor did not cover the relationship between work and components in class, leading to uncertainty. There is also mention of examples from the textbook that do not align with the current problem setup, contributing to confusion.

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Homework Statement


If c represents a constant force, find the work done if the point of application of c moves along the line segment from P to Q.
(Hint: Find a vector b = (b1, b2) such that b is a vector of PQ)

c = -i+7j P(-2,5) Q(6,1)

Homework Equations


Components...but I am not sure. Dot Product.


The Attempt at a Solution


We went over components and dot product in class, but not how it relates to work. I'm not even sure to begin with this one.
 
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TrueStar said:
We went over components and dot product in class, but not how it relates to work.

Hi TrueStar! :smile:

work done = force "dot" displacement (of the point of application of the force). :wink:
 
Thanks. :) I've researched it myself..I tried the problem and the answer I got was 32. I found many examples where one of the vectors was at the origin, but not two vectors with different components.

This is what's throwing me off. Then again, maybe I got the right answer. I don't know yet.
 
Maybe you've used the wrong vector for PQ.

Show us how you got 32. :smile:
 
Thanks Tim:

I made a mistake. I think it's 36. I kind of did it my own way. I knew how to get the answer if one of the vectors was at (0,0). So, I picked -2,5 and decided that I needed to add two to x and subtract 5 from y. I did this to the other vector which changed its components from 6,1 to (8,-4).

I then used dot product with (8,-4) and -i+7j and got -36. I noticed similar problems to this had positive answered, so I put down 36.

I know..I'm horrible. I'd rather put something down instead of nothing at all.
 
TrueStar said:
Thanks Tim:

I made a mistake. I think it's 36. I kind of did it my own way. I knew how to get the answer if one of the vectors was at (0,0). So, I picked -2,5 and decided that I needed to add two to x and subtract 5 from y. I did this to the other vector which changed its components from 6,1 to (8,-4).

I then used dot product with (8,-4) and -i+7j and got -36. I noticed similar problems to this had positive answered, so I put down 36.

I know..I'm horrible. I'd rather put something down instead of nothing at all.

D'oh! :rolleyes:

You got it right, and then you changed it so as to "conform".

It is -36 … this particular one comes out negative because the force is in (roughly) the opposite direction to the displacement …

eg what work does gravity do when a roller-coaster goes up? Obviously, negative! :smile:

This is the way to do it …

(btw, don't talk about "changing the components" of a vector … you can't do that to vectors (well, unless you're changing the frame of reference, or the basis)! … talk about subtracting them … that is the official word … they form a "vector space" under addition subtraction and scalar multiplication :wink:)

P = (-2,5) Q = (6,1), so PQ = Q - P = (8,-4) or 8i - 4j

c = (-1,7) or -i + 7j

Then you can find c.PQ either by doing (8,-4).(-1,7) or (8i - 4j).(-i + 7j),

(both are perfectly valid)

and either way it's -8 -28 = -36 :wink:
 
Oh wow..I just can't believe I got as much correct as I did! The instructor never talked about the concept of work in relation the the topic (components). Our textbook has examples of this where one was at the origin, but not like this one.

I apologize for my incorrect terminology, this is all new to me and I have yet to take a physics class.

Thank you so much for helping me out and explaining everything so clearly. I really appreciate it!
 

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