Finding a Force using the dot product/projection (Calc 3)

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    Calc 3 Dot Force
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SUMMARY

The discussion focuses on calculating the force required to prevent a 600-pound boat from rolling down a ramp inclined at 30 degrees, as presented in Larson's Calculus Early Transcendentals (4th Ed, Pg. 786). The key equation used is the vector projection formula, specifically w1 = projvF = [(F * v) / ||v||²] = (F * v)v. The confusion arises regarding the simplification of the norm squared in the projection formula, with clarification provided that this simplification is valid when dealing with unit vectors.

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  • Understanding of vector projection in calculus
  • Familiarity with Larson's Calculus Early Transcendentals
  • Knowledge of basic trigonometry, specifically angles and forces
  • Concept of unit vectors and their properties
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  • Review the properties of unit vectors and their applications
  • Practice problems involving forces on inclined planes
  • Explore advanced topics in vector calculus, such as gradient and divergence
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Students studying calculus, particularly those in Calculus 3, as well as educators and tutors looking to clarify concepts related to vector projections and forces on inclined surfaces.

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Homework Statement



This is from Larson's Calculus Early Transcendentals 4th Ed (Pg. 786)

A 600-pound boat sits on a ramp imclined at 30 degrees, as shown in Figure 11.32. What force is required to keep the boat from rolling down the ramp?

Homework Equations



The solution gives the following equation: w1 = projvF = [(F * v) / ||v||2] = (F * v)v

The Attempt at a Solution



This is just an example in the book, and I'm confused about how the author did the last two steps in the previous equation. I think it's just one of those omissions where it's really simple, but I can't figure out why the length of the vector squared can just disappear.
 
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The second to last step makes sense, since that's just the vector projection formula:
[tex]\frac{(\vec{u}\cdot\vec{v})\vec{v}}{v^2}[/tex]
is the projection of [itex]\vec{u}[/itex] on to [itex]\vec{v}[/itex]. But I'm not understanding the last step. The norm squared can't just disappear like that, unless it's a unit vector (in which case the norm is 1).
 
Someone just told me it is a unit vector, but thanks for your help anyway! I had been wondering if that could just "cancel" or or not...
 

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