Finding a friction force (ladder leaning against a wall )

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Linus Pauling
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1.
Free-body diagram of a worker standing partway up a leaning ladder against a wall, with labelled masses m1 and m2, length L, distance d, angle theta, and normal forces N1 and N2 and friction f.


Suppose that the actual coefficient of friction is one and a half times as large as the value of . That is, . Under these circumstances, what is the magnitude of the force of friction that the floor applies to the ladder?
Express your answer in terms of , , , , , and . Remember to pay attention to the relation of force and .




2. static friction = magnitude of force in x direction, opposite sign



3. Ok, I had two exams today and I just almost went crazy calculating the the minimum friction force so that this ladder won't slip (brutal, but I did it). I am burnt out. How do I calculate N_1 here? It's the only force in the x direction other than friction, right? So by Newton's 2nd law the answer should just be friction = 1.5N_1, right?
 
... that picture has everything except that calculated minimum friction force, which is:

cot(theta) * (Lgm_2 + M_1gd - 0.5m_dLg * (Lgm_1 + Lgm_2)^-1