Finding a Linear Transformation T: R2 -> R2 with Equal Null Space and Range

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The discussion focuses on finding a linear transformation T: R2 -> R2 where the null space equals the range. Participants explore the implications of the rank-nullity theorem, noting that both dimensions must be 1 for the null space and range to be equal. A suggested transformation is T(x, y) = (x - y, x - y), which leads to a null space of {(x, y) : x = y} and a range of all outputs of the form (c, c). Another example provided is A(x, y) = (y, 0), which also meets the criteria. The conversation emphasizes the importance of selecting appropriate subspaces to achieve the desired transformation.
amanda_ou812
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Homework Statement


Give an example of a linear transformation T: R2 -> R2 such that the null space is equal to the range.


Homework Equations


null space and range


The Attempt at a Solution


I have been trying to come up with a solution but I cannot figure it out. What might be a logical methodology.
 
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Well, you know the dimension of the null space plus the dimension of the range must be 2 by the rank nullity theorem. If you want them to be the same subspace, what should the dimension be? That's a good place to start.
 


well dim V is 2 so nullity and rank have to each be 1. I know that N(T) is a subset of V and R(T) is a subset of W so if R(T) = N(T) = a set with one vector and that vector will belog to both V and W...i guess that thought process does not get me closer to a conclusion.
 


amanda_ou812 said:
well dim V is 2 so nullity and rank have to each be 1. I know that N(T) is a subset of V and R(T) is a subset of W so if R(T) = N(T) = a set with one vector and that vector will belog to both V and W...

Ok, so pick anyone dimensional subspace of R^2. What's your favorite? Now cook up a linear transformation that maps any vector into that one dimensional subspace and any vector in that subspace into zero. It helps to be concrete about what the subspace is.
 


I am not really sure if this is what you mean...
so, I choose y=x as my one dim subspace of R2. So I could do T(x, y) = (x,x).
but what do you mean by mapping any vector in this subspace into zero?
If I use this transformation my R(T) = (1, 1) and my N(T) = c (0, 1)...I feel like I am close to getting the answer..
 


amanda_ou812 said:
I am not really sure if this is what you mean...
so, I choose y=x as my one dim subspace of R2. So I could do T(x, y) = (x,x).
but what do you mean by mapping any vector in this subspace into zero?
If I use this transformation my R(T) = (1, 1) and my N(T) = c (0, 1)...I feel like I am close to getting the answer..

There's not just one answer. You are getting close. Here's BIG hint: suppose you pick T(x,y)=(x-y,x-y)? What are the range and null space? Now find another answer, my favorite subspace is x=0. Find a T that works with that.
 
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ahhh... I see now. N(T) = {(x, y) : x=y} or {c (1, 1)} for C in R and R(T) (which is all the outputs that are the same as the inputs - is how I like to think of it) will be (a1, a1) = c (1, 1) geez

I kept trying (x-y, 0) but i never thought to do (x-y, x-y) thanks!
 


Good! And now that you have that, here's another, simpler example: A(x, y)= (y, 0).
 

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