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Finding a Maclaurin series for ln(x)

  1. Dec 6, 2009 #1
    Since ln(0) doesn't exist, this question is futile right?

    I am tasked with finding a Maclaurin powerseries for ln(x) and to find out how many times I have to run that series to get a accurate answer for ln(1.5).

    What should I do? Should I find the taylor series for ln(1.5) for should I find the Maclaurin for ln(1 + x) and find out what .5 is instead of 1.5.

    Thanks.
     
  2. jcsd
  3. Dec 6, 2009 #2
    Seems like the better choice (Maclaurin for [itex]ln(1 + x)[/itex] or Taylor of [itex]ln(x)[/itex] about [itex]x=1[/itex]) - this may be what was intended all along. However, you should clarify with instructor.
     
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