- #1

nabilsaleh

- 14

- 0

Lets try this for example:

The joint p.d.f of the continuous random variable X and Y is:

f(x,y)= (2y+x)/8 for 0<x<2 ; 1<y<2

now we're asked to find a probability, say P(X+Y<2)

I know i have to double integrate but how do I choose my integration limits and what do I do after I finish integrating?

My Attempt at the solution is:

P(X+Y<2) = \int_ \int (2y+x)/8 = 1 = \int [y^2/8 + xy/ 8]