Finding a second velocity with a first and average velocity

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A car travels at a constant speed of 44.5 mi/h for a distance d and then at an unknown speed for the same distance, resulting in an average velocity of 28.5 mi/h. The initial approach using the average of the two speeds was incorrect, as it does not account for the time spent at each speed. Instead, a weighted average formula should be applied, relating total distance and total time. The correct calculation reveals that the second speed is 21 mi/h, aligning with the answer key. The discussion emphasizes the importance of using appropriate equations for problems involving varying speeds.
Heidi

Homework Statement


A car travels along a straight line at a constant speed of 44.5 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 28.5 mi/h. NOTE: this is a practice problem.

Homework Equations


V_avg=(V_i+V_f)/2

The Attempt at a Solution


28.5=44.5/2+V_f/2
28.5*2-44.5=V_f
V_f=12.5 mi/h
This is not correct because the answer sheet says that the answer is 21 mi/h. I have been trying different ways including a proportionality using distance and time, but I cannot seem to get 21 as any of my answers. I feel as if none of the equations I have been given help with this problem because there is no acceleration or exact time and exact distance.
 
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Try using a weighted average as your relevant equation, rather than the mean of the velocities, which assumes an equal time traveled at each velocity.
 
MarkFL said:
Try using a weighted average as your relevant equation, rather than the mean of the velocities, which assumes an equal time traveled at each velocity.
How might I go about doing that then? It would give me two unknowns instead of just one.
 
Heidi said:
How might I go about doing that then? It would give me two unknowns instead of just one.

I would begin by stating:

##\displaystyle\overline{v}=\frac{v_1t_1+v_2t_2}{t_1+t_2}##

Now, you are given ##\overline{v}## and using the relation ##d=vt##, can you express the RHS in terms of everything else given, as well as the unknown velocity?
 
Your expression for the average velocity (or more correctly speed in this case) is total distance traveled divided by total time required to travel that distance.
 
MarkFL said:
I would begin by stating:

##\displaystyle\overline{v}=\frac{v_1t_1+v_2t_2}{t_1+t_2}##

Now, you are given ##\overline{v}## and using the relation ##d=vt##, can you express the RHS in terms of everything else given, as well as the unknown velocity?
MarkFL said:
I would begin by stating:

##\displaystyle\overline{v}=\frac{v_1t_1+v_2t_2}{t_1+t_2}##

Now, you are given ##\overline{v}## and using the relation ##d=vt##, can you express the RHS in terms of everything else given, as well as the unknown velocity?
I finally got it figured out. I was supposed to use the distance/speed formula. Thank you for your help anyway!
 
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