Finding a solution to the equation x3^(2x+1)=9x

[Mppl]

how can I know that zero is the solution of x3^(2x+1)=9x

I mean I know that it is the solution cause if I substitute zero I'll get an equality but how can I find it?

 

[3.1415926535]

Is this the equation you want to solve:
$$x3^{2x+1}=9x$$?
If so, $$x3^{2x+1}=9x\Leftrightarrow x(3^{2x+1}-9)=0\Leftrightarrow x=0\text{ or } 3^{2x+1}=3^2\Leftrightarrow 2x+1=2\Leftrightarrow x=\frac{1}{2}$$

 

[Mppl]

oh thanks man, all I could think about was to divide both sides by x. Thats so simple...

Thank you very much

 

[3.1415926535]

Just happy to help