Finding a solution to the equation x3^(2x+1)=9x

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Mppl
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how can I know that zero is the solution of x3^(2x+1)=9x

I mean I know that it is the solution cause if I substitute zero I'll get an equality but how can I find it?
 
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Is this the equation you want to solve:
x3^{2x+1}=9x?
If so, x3^{2x+1}=9x\Leftrightarrow x(3^{2x+1}-9)=0\Leftrightarrow x=0\text{ or } 3^{2x+1}=3^2\Leftrightarrow 2x+1=2\Leftrightarrow x=\frac{1}{2}
 
oh thanks man, all I could think about was to divide both sides by x. Thats so simple...

Thank you very much
 
Just happy to help
 

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