Finding AC voltage across Resistor

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SUMMARY

This discussion focuses on calculating AC voltage across a resistor in circuits with both AC and DC components. The key equation mentioned is Voltage across resistor = I * R, though its applicability in mixed current scenarios is questioned. The user attempted various methods, including removing the battery and using maximum and minimum voltage values, but struggled to achieve accurate results. The final answer provided for the AC voltage across the resistor is 1.08V, derived from the load line equation V(ec) = 12 - 6000 * I(c).

PREREQUISITES
  • Understanding of AC and DC circuit principles
  • Familiarity with Ohm's Law (Voltage = Current * Resistance)
  • Knowledge of load line analysis in circuit theory
  • Basic skills in interpreting circuit diagrams
NEXT STEPS
  • Study the impact of superposition theorem in circuits with AC and DC components
  • Learn about phasor representation of AC voltages and currents
  • Explore load line analysis in more depth, particularly for mixed signals
  • Investigate the use of oscilloscopes for measuring AC voltage in circuits
USEFUL FOR

Students and professionals in electrical engineering, particularly those dealing with circuit analysis involving both AC and DC signals, as well as anyone preparing for advanced physics topics related to electricity and circuits.

Acuben
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Homework Statement



I have three questions
1. How do you find AC voltage across resistor when there are both AC and DC current?
2. is AC voltage across a resistor different from voltage across a resistor?
3. Find AC voltage across Resistor (in this image)
http://img199.imageshack.us/i/acv.gif/
load line Eq: V(ec)=12-6000*I(c)
answer: 1.08v

Homework Equations


Voltage across resistor = I*R
but I do not know if this can be used when there are mixture of

The Attempt at a Solution


well I tried making a AC current by removing battery out of the circuit. I would still get around 3 volts. Also tried using V(max) and V(min) and calculated for I*R(l), but got around 6 volts (which is way off)
now I'm out of ideas. (well I do not understand the problem fully in the first place)
Do I need to use the chart on the bottom?
by the way, does this topic (or anything under circuits, electric fields, and optics-related physics) belong to advanced physics? or is this in the right section?)
 
Last edited:
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can I simply find
I(c) max and I(c) min and find both voltage of V(ec) then find the difference divided by 2?
 

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