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Introductory Physics Homework Help
Finding acceleration and tension on an incline
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[QUOTE="soysauce, post: 4527473, member: 490165"] [h2]Homework Statement [/h2] Hi everyone, I hope you're enjoying your weekends! I've been trying this question for a while not having any luck, I'm hoping someone can tell me where I'm going wrong The question is: Two boxes are connected by a rope that passes through a pulley on the corner of a incline. Box A is 2.5 kg and box B is 5.5 kg. The coefficient of kinetic friction on the incline is 0.54. Box A is on the incline and box B hangs over. The angle of the incline is 25.4º. Find the acceleration and the tension. The answers given are 3.8 m/s2 [down] and 33 N [up] [h2]Homework Equations[/h2] I got these equations from here:[url]https://www.physicsforums.com/showthread.php?t=27346[/url] and I understand why I would use them F[SUB]t[/SUB] = m[SUB]1[/SUB] *a + m[SUB]1[/SUB]gcosθ + μm[SUB]1[/SUB]gcosθ and F[SUB]t[/SUB] = m[SUB]2[/SUB](g-a) [h2]The Attempt at a Solution[/h2] m1 = 2.5 kg, m2 = 5.5 kg, μ = 0.54, θ = 25.4° I know I can equate the two tension equations to get: m[SUB]2[/SUB](g-a) = m[SUB]1[/SUB] *a + m[SUB]1[/SUB]gcosθ + μm[SUB]1[/SUB]gcosθ But when I plug in the known values and solve: 5.5(9.8-a) = 2.5*a + 2.5*9.8*cos(25.4) + 0.54*2.5*9.8cos(25.4) I get a value of a = 2.4 Could someone tell me where I'm going wrong here? Thanks so much in advance! [/QUOTE]
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Introductory Physics Homework Help
Finding acceleration and tension on an incline
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