Finding accleration of object after collision

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Homework Help Overview

The discussion revolves around a physics problem involving the collision of two basketball players, focusing on the acceleration experienced by each player post-collision. The subject area includes concepts from dynamics, specifically Newton's laws of motion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster seeks guidance on how to determine the acceleration of player 2 after knowing player 1's mass and acceleration. Participants discuss the application of Newton's laws, particularly the relationship between forces exerted during the collision.

Discussion Status

Participants are actively engaging with the problem, with some providing insights into the application of Newton's second and third laws. There is an exploration of the implications of negative and positive forces in the context of the collision, indicating a productive dialogue without a clear consensus yet.

Contextual Notes

The original poster is under time constraints due to a correspondence course and is looking for clarification rather than a complete solution. There is a focus on understanding the forces involved in the collision and their directional implications.

Adam17
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1. Two basketball players collide. Player 1, with a mass of 55.0 kg, experiences a -15.6 m/s2 acceleration. If player 2 has a mass of 48.5 kg, what acceleration did he experience immediately following the collision?




Homework Equations

F=ma

I am doing a correspondance course and I don't understand how to figure this out... don't need a solution but just directions on how to solve this.
 
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Welcome to PF,

You know the net force on player 1, because you know his mass, and you know his acceleration. (See Newton's 2nd law).

Now apply Newton's Third law to the problem. What does it say is the relationship between the force on player 1 due to player 2 (which you know), and the force on player 2 due to player 1 (which you need to know)?
 
Ok thanks for your help. Glad I found this forum though or else Id have to wait till monday to talk to my teacher and I need this course done asap.
 
So this is what I got and I am confident that it is correct, however I am unsure about the negative. Would the force that I calculated from player 1 be in the same direction as the acceleration
?(away from the collision) Making the Force applied to player 2 positive?

F=ma
Fp1=55(-15.6)
Fp1=-858

A=f/m
Ap2=-858/48.5
Ap2=-17.6m/s^2
 
The negative force is the force player 2 exerts on player 1, not the force player 1 exerts on player 2.
 
Last edited:
Xisune said:
The negative force the force player 2 exerts on player 1, not the force player 1 exerts on player 2.

Ohhhh right. Thanks Xisune.
 

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