Finding amount of graphite in a Pencil

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Homework Help Overview

The discussion revolves around calculating the percentage of graphite in a pencil, specifically a 2H pencil, using electrical properties such as current, voltage, and resistivity. The original poster provides measurements and attempts to apply Ohm's law and resistivity formulas to derive the necessary values.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster calculates resistance and resistivity based on given electrical parameters and seeks confirmation on their calculations. Some participants question the assumptions made regarding the relationship between conductivity and the composition of the pencil, particularly in relation to the presence of insulating materials.

Discussion Status

Participants are exploring the validity of the original poster's calculations and assumptions. There is a focus on clarifying the nature of the materials involved, with some guidance offered regarding the conductivity of different materials. The discussion is ongoing, with no explicit consensus reached yet.

Contextual Notes

There is a mention of potential assumptions regarding the conductivity of materials mixed with graphite, as well as considerations about the types of paints used on pencils that may affect conductivity. The goal of the original poster's experimentation is clearly stated as finding the amount of graphite in the pencil.

Manty
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Homework Statement



I have some information about a 2H pencil. There is a current of 0.008 amps and 3.8 volts going through the pencil. The length of the pencil was 16cm and the diameter of the core was 2mm. Calculate the percentage of graphite in the pencil.

Homework Equations


ohms law
V= I. R

resistivity
R=(ρ.L)/(A)

The Attempt at a Solution


i calculated the resistance to be 47.5 ohms, using ohms law.
i then substituted of my known values into the resistivity formula

R=47.5
A=3.14159E-06 meters squared
L=0.16meters

47.5 =(ρ.0.16)/(3.14159E-06 )
ρ=0.00093266 ohm meters

Is this correct so far?
Also what is the resistivity of graphite ?
 
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You seem to assume there is a linear relationship kg/k = parts graphite, where k is the conductivity of your sample and kg the conductivity of graphite.

I'm fairly sure this is not the case for a mixture of two materials where the conductivity of the insulating material is small enough to be assumed zero.

Ask, "are metalic paints conductive?" I don't believe they commonly are, however there are paints containing silver metal, forumated specifically to conduct well.
 
Phrak said:
Ask, "are metalic paints conductive?" I don't believe they commonly are, however there are paints containing silver metal, forumated specifically to conduct well.
Just don't get pencils with metallic paints... simple

Just use those plain, boring, brown pencils... :-p
 
what must i do to get on the right track?
 
Manty said:
what must i do to get on the right track?

What is the goal of your experimenting?
 
To find the amount of graphite in the pencil
 

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