Finding Amplitude of a Mass on a Spring | Simple Harmonic Motion

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SUMMARY

The discussion focuses on calculating the amplitude of a mass oscillating on a spring under simple harmonic motion. A 12.5 kg mass is attached to a spring with a spring constant of 1e^5 N/m, resulting in a frequency of 89.44 1/s. The amplitude was determined to be 10.83 cm, and the phase angle (φ) was calculated to be 26.895 degrees. However, there was confusion regarding the position calculation at t = 0.0149 seconds, where the user obtained a position of 6.993 cm, which was marked incorrect by the system.

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  • Understanding of simple harmonic motion principles
  • Familiarity with spring constants and mass-spring systems
  • Knowledge of trigonometric functions in physics equations
  • Ability to apply initial conditions to harmonic motion equations
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  • Review the derivation of the simple harmonic motion equation y(t) = A sin(wt + φ)
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  • Explore the impact of phase angle on oscillation behavior
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Simple Harmonic Motion- Spring problem

Homework Statement



A 12.5 kg mass is suspended on a 1e^5 N/m spring. The mass oscillates up and down from the equilibrium position
[tex]y(t)= Asin(wt+\phi)[/tex]

Find the amplitude of the oscillating mass

Initial position- 4.9 cm
Initial velocity= +8.64 m/s
Time= 0

Homework Equations


No idea, see below


The Attempt at a Solution


Ok, I found the frequency, which is 89.44 1/s. But, I don't know how to figure out the amplitude of this thing with the information given. I've looked, and I can't find a formula to use. If someone could show me what formula I'm supposed to use, it would be greatly appreciated.
 
Last edited:
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Ok, I figured out the amplitude and the phi. But, here's the latest part of the question

Calculate the position @ t=.0149 seconds

If A=10.83 cm
w= 89.44 (1/s)
Phi= 26.895 degrees

Plugging that into the equation, I get 6.993, yet the system says it's wrong. It also says to answer in cm, but I'm not seeing any discrepencies here. >.>
 

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