- #1
PolarBee
- 14
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Homework Statement
There is a thin rod with charge Q that has been bent into a semicircle with radius R. Find an expression for the electric potential at the center.
Radius = R
Charge = Q
Homework Equations
V = ∫(k * dq)/r
The Attempt at a Solution
dq = λdx
λ = Q/L
L = pi * r
V = kQ / LR ∫ dx = kQ / pi * r^2 ∫ [3pi/2 - pi/2]
V = kQ/R^2
But the answer should be kQ/R. How did the other R get cancelled?