How Can I Calculate Position z(t) from Velocity as a Function of Position?

  • Thread starter Thread starter henryc09
  • Start date Start date
Click For Summary
To calculate position z(t) from velocity as a function of position, the discussion highlights the need to integrate the velocity function v(z). The user initially confused variables, mistakenly using y instead of z, but clarified that they have derived v(z). The key challenge is integrating v(z) with respect to time, as it requires expressing v as a function of time. The conversation emphasizes the importance of correctly defining variables and understanding the relationship between position, velocity, and acceleration in this context. Integration is essential for finding z(t) from v(z).
henryc09
Messages
68
Reaction score
0

Homework Statement


I have a problem where I have a force and therefore acceleration which depends on position, z. Using z'' = dv/dt = dv/dy * dy/dt = v*dv/dy I was able to find velocity as a function of position.

It nows asks for z(t). I'm having a bit of a mental block here and don't know how to go about finding this. Any help would be appreciated!


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org


henryc09 said:

Homework Statement


I have a problem where I have a force and therefore acceleration which depends on position, z. Using z'' = dv/dt = dv/dy * dy/dt = v*dv/dy I was able to find velocity as a function of position.
I'm confused by your choice of variables in this problem. The usual variables that are used in problems of this type are s for position, v for velocity, and a for acceleration, where v = ds/dt, and a = dv/dt = d2s/dt2.

What does y represent in your problem?
henryc09 said:
It nows asks for z(t). I'm having a bit of a mental block here and don't know how to go about finding this. Any help would be appreciated!
 


sorry I messed that up, wherever I put y I meant z.

so i found v(z)
 


What do you have for v(z)? The usual thing to do with velocity to find position is to integrate, but for that you would need to integrate with respect to time, and v would have to be a function of t.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

Replies
21
Views
2K
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
13
Views
3K
Replies
32
Views
3K
  • · Replies 13 ·
Replies
13
Views
5K
Replies
10
Views
2K