Finding Applied force given Mass and Kinetic and Static coefficients.

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SUMMARY

The discussion centers on calculating the applied force required to move a refrigerator with a mass of 180 kg, given the coefficients of kinetic and static friction (0.13 and 0.21, respectively). The normal force is determined to be 1764 N, leading to a static friction force of 370.44 N and a kinetic friction force of 229.32 N. To initiate movement, a horizontal force of at least 370.44 N must be applied, as static friction must be overcome before kinetic friction takes effect. The net force required to achieve acceleration after overcoming static friction is calculated as 141.12 N, resulting in an acceleration of 0.784 m/s².

PREREQUISITES
  • Understanding of Newton's laws of motion (Fnet = ma)
  • Knowledge of friction coefficients (static and kinetic)
  • Ability to calculate normal force and gravitational force
  • Basic algebra for solving equations
NEXT STEPS
  • Study the principles of static and kinetic friction in detail
  • Learn how to calculate normal force in various scenarios
  • Explore real-world applications of friction in mechanical systems
  • Investigate the effects of different surface materials on friction coefficients
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Students in physics, mechanical engineers, and anyone interested in understanding the dynamics of moving heavy objects and the forces involved in overcoming friction.

Hieroglyphics
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Homework Statement


Your family just had anew refrigerator delivered. The delivery man has left and you realize that the refrigerator is not quite in the right position, so you plan to move it several centimeters. If the refrigerator has a mass of 180 kg, the coefficient of kinetic friction between the bottom of the refrigerator of the floor is 0.13, and the static coefficient of friction between these same surfaces is 0.21, how hard do you have to push horizontally to get the refrigerator to start moving?


Homework Equations


The one's I'm thinking of are:
Fnet = ma
Fnµ = Ff

The Attempt at a Solution



So I found the Normal Force and Force of Gravity are 1764 obviously

Force of kinetic friction is 229.32, force of static friction is 370.44
and I think I can do 370.44-229.32 = Fnetx so that Fnetx = 141.12
so then I would know ma = 141.12 so a = .784.

But I'm stuck after that :(
 
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Hieroglyphics said:

Homework Statement


Your family just had anew refrigerator delivered. The delivery man has left and you realize that the refrigerator is not quite in the right position, so you plan to move it several centimeters. If the refrigerator has a mass of 180 kg, the coefficient of kinetic friction between the bottom of the refrigerator of the floor is 0.13, and the static coefficient of friction between these same surfaces is 0.21, how hard do you have to push horizontally to get the refrigerator to start moving?


Homework Equations


The one's I'm thinking of are:
Fnet = ma
Fnµ = Ff

The Attempt at a Solution



So I found the Normal Force and Force of Gravity are 1764 obviously

Force of kinetic friction is 229.32, force of static friction is 370.44
and I think I can do 370.44-229.32 = Fnetx so that Fnetx = 141.12
so then I would know ma = 141.12 so a = .784.

But I'm stuck after that :(
You cannot have static friction and kinetic friction acting at the same time. Static friction acts only when the object is not moving with respect to the surface it is in contact with, and kinetic friction acts only when the object is moving with respect to the surface it is in contact with. Just before the refrigerator starts moving, which type friction force applies? Is there any acceleration of the refrigerator before it starts to move? What force must be applied at the instant just before it starts to move?
 

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