Finding area of the affine translation of a rectangle

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SUMMARY

The area of the affine translation of the rectangle R = [1,3] x [2,4] is calculated using the determinant of the transformation matrix A, which is defined as A = [[2, 7], [3, 1]]. The area of the rectangle R is initially 4, derived from the product of its side lengths (2 x 2). The correct area after applying the affine transformation is 76, obtained by multiplying the original area by the determinant of A, which equals 19. Therefore, the area of the affine translation is confirmed as 76.

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  • Familiarity with calculating areas of rectangles
  • Basic concepts of vector operations (cross product in R^3)
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yomakaflo
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Homework Statement


Given a rectangle R=[1,3] x [2,4], and the affin translation F : R^2 -> R^2 defined by F(x,y) = (1,3) + A*(x,y), where A is the 2x2 matrix (2 , 7 ; 3 , 1), what is the area of the affin transelation of the rectangle R?

Homework Equations

The Attempt at a Solution


When I cross the vectors of R I get the scalar 2. Is this the area of R before we transelate it? The determinant of A equals 19, and 2*19=38. So this is my answer and it is wrong. Right answer is 76, so I guess the area of R before translation should be 76/det(A)=4. Where am I wrong?
 
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The area of R is obiously 2x2=4 and it must be multiplied by 19 to get the translated area. What are the "vectors of R" that you crossed? Show us that.
 
R = [1,3] cross [2,4], so I think the vectors of R are [1,3] and [2,4] . When they are crossed the product is abs(4-6) = 2. I want the answer to be 4, but I don't know how!
 
yomakaflo said:
R = [1,3] cross [2,4], so I think the vectors of R are [1,3] and [2,4] . When they are crossed the product is abs(4-6) = 2. I want the answer to be 4, but I don't know how!

Those are not the correct vectors to cross. You want the vectors along the sides of the square.
 
yomakaflo said:
R = [1,3] cross [2,4], so I think the vectors of R are [1,3] and [2,4] . When they are crossed the product is abs(4-6) = 2. I want the answer to be 4, but I don't know how!
In addition to what LCKurtz said, those aren't even vectors -- they are intervals along the x and y axes. Also, I don't know what you are doing when you say you are "crossing" these vectors. The vector cross product is defined for vectors in R3.
 
Mark44 said:
In addition to what LCKurtz said, those aren't even vectors -- they are intervals along the x and y axes. Also, I don't know what you are doing when you say you are "crossing" these vectors. The vector cross product is defined for vectors in R3.

Okey, I misunderstood R = [1,3] x [2,4]. Then i makes sense that the area of R is 4 and 4*19=76 after the translation. Thanks!
 

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