Finding Centroid of Triangle in First Quadrant

  • Thread starter Thread starter magma_saber
  • Start date Start date
  • Tags Tags
    Centroid
Click For Summary
SUMMARY

The centroid of the triangular region in the first quadrant, bounded by the line 4x+y=4, the x-axis, and the y-axis, can be calculated using the equations x̄ = My/M and ȳ = Mx/M. The correct limits for integration are determined by the boundaries of the triangle, specifically from y=0 to y=4 and x=0 to x=(4-y)/4. A sketch of the region aids in visualizing the integration limits and ensuring accuracy in calculations.

PREREQUISITES
  • Understanding of double integrals in calculus
  • Familiarity with the concept of centroids in geometry
  • Knowledge of setting up limits of integration for triangular regions
  • Ability to interpret and sketch geometric figures
NEXT STEPS
  • Study the process of calculating centroids for various geometric shapes
  • Learn about double integrals and their applications in finding area and volume
  • Explore the use of sketches in determining limits of integration
  • Practice problems involving integration of triangular regions
USEFUL FOR

Students studying calculus, particularly those focusing on integration and geometric applications, as well as educators seeking to enhance their teaching methods for centroid calculations.

magma_saber
Messages
73
Reaction score
0

Homework Statement


Find the centroid of the triangular region in the first quadrant bounded by the line 4x+y=4, the x-axis, and the y-axis.


Homework Equations


\int\int\deltadA
xbar = My/M
ybar = Mx/M

The Attempt at a Solution


Is the boundary for the dy from 0 to 4, and dx from 0 to 4-4x?
 
Physics news on Phys.org
No, your limits for x can't contain x. They can only depend on y.
 
so its y-4/4?
also are my limits for dy correct?
 
No, that's not quite correct either. (I assume you mean (y-4)/4, not y-1.) You should always plug in a few values to do a sanity check. In this case, when y=0, you'd get a negative answer.

Your limits for y are fine. (But I'll note I'm saying this under the assumption that you set things up correctly.)

Did you draw a sketch of the region of integration?
 
the region would be the triangle from y=4 to y=0 and x=0 and x=1 right?
and is the limit 4-4x?
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K