How do you find the centroid of this?

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Homework Help Overview

The discussion revolves around finding the centroid of a shape defined by the equation y² = x³ - x⁴, along with the x-axis and y-axis. Participants are exploring various methods to evaluate the necessary integrals for determining the centroid.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss attempts at using u-substitution and express uncertainty about the applicability of other methods like trigonometric substitution and partial fractions. There is mention of trying polar coordinates, though some participants express hesitation about moving away from Cartesian coordinates.

Discussion Status

There is ongoing exploration of different approaches, including suggestions to consider polar coordinates as an alternative. Some participants are questioning the appropriateness of their current methods and the expectations of their instructor regarding the coordinate system to be used.

Contextual Notes

Participants note confusion regarding the integral setup and the swapping of variables in the equations for Mx and My. There is also a concern about the teacher's preferences for solving the problem.

Manwe Sulimo
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Homework Statement


Find the centroid of the shape formed by the equation y2=x3-x4, the x-axis, and the y-axis.

Homework Equations


A=∫f(x)dx
Mx=∫(1/2)[f(x)]2dx
My=∫x[f(x)]dx

The Attempt at a Solution


I'm stuck on the integral.
I attempted u-substitution and got du=(1/2)(x3-x4)-1/2dx; "parts," trigonometric substitution/identities, and partial fractions don't seem to apply.
 
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Manwe Sulimo said:

Homework Statement


Find the centroid of the shape formed by the equation y2=x3-x4, the x-axis, and the y-axis.

Homework Equations


A=∫f(x)dx
Mx=∫(1/2)[f(x)]2dx
My=∫x[f(x)]dx

The Attempt at a Solution


I'm stuck on the integral.
I attempted u-substitution and got du=(1/2)(x3-x4)-1/2dx; "parts," trigonometric substitution/identities, and partial fractions don't seem to apply.
Try polar coordinates.
 
SammyS said:
Try polar coordinates.
I haven't worked in those for a while (I'm not sure I remember how to use them); but I'm fairly certain my teacher wants me to stick with x-y coordinates.
 
Manwe Sulimo said:
I haven't worked in those for a while (I'm not sure I remember how to use them); but I'm fairly certain my teacher wants me to stick with x-y coordinates.
You've already tried trig substitutions. Think of polar coordinates as a form of trig substitution.

Besides, what will your teacher prefer? That you kept working with cartesian coordinates and didn't solve the problem, or you converted to polar coordinates and got an answer? :wink:
 
Manwe Sulimo said:

Homework Statement


Find the centroid of the shape formed by the equation y2=x3-x4, the x-axis, and the y-axis.

Homework Equations


A=∫f(x)dx
Mx=∫(1/2)[f(x)]2dx
My=∫x[f(x)]dx
You swapped ##M_x## and ##M_y##.

The Attempt at a Solution


I'm stuck on the integral.
I attempted u-substitution and got du=(1/2)(x3-x4)-1/2dx; "parts," trigonometric substitution/identities, and partial fractions don't seem to apply.
Try starting like this:
$$\int x\sqrt{x^3-x^4}\,dx = \int x^2\sqrt{x-x^2}\,dx = \int x^2\sqrt{\frac 14-\left(x-\frac 12\right)^2}\,dx.$$ The last step comes from completing the square. Then try a few more substitutions and see if you get anywhere.
 
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