at a point midway between two point charges separated by 0.10 meters, the magnitude of the electric field is 10V/m and the electric potential is zero. what are the two charges
electric potential - > point charge V = kq/r
electric potential difference = electric potential V = kq [(1/r_B) - (1/r_A)] where r is the distance, k is constant = 9*10^9, q is charge in coulombs
electric field E = qF where q is charge, F is force in newtons
force F = kq_1q_2/r^2
The Attempt at a Solution
r = 0.05m
I need to be able to isolate the two charges so that i can solve for one and then subsitute the value in to solve for the other.
if i use electric potential difference eq, how do i involve two charges? the radii should be the same, correct? but if radii are the same won't i get zero in the  and then q = 0. also if i use that equation i will not be able to factor in electric field.
i am supposed to get q_A = -q_B = 1.39*10^-12 coulombs