Finding coefficient of friction given slope

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To find the coefficient of kinetic friction for a skier coasting down a 3.5-degree slope at constant speed, it's essential to analyze the forces acting on the skier. The normal force is equal to the component of gravitational force acting perpendicular to the slope, while the frictional force opposes the motion and is proportional to the normal force. To solve the problem, the weight of the skier must be split into two components: one parallel to the slope and one normal to it. The relationship between the frictional force and the normal force can then be used to calculate the coefficient of friction. Understanding these force components is crucial for determining the coefficient of kinetic friction.
Carriebun
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Homework Statement



A skier coasts down a 3.5 degree slope at a constant speed. Find the coefficient of kinetic friction between the skis and the snow covering the slope.


Homework Equations



coefficient of friction x Normal force = force friction

therefore: coefficeint of friction = force friction / normal force

The Attempt at a Solution



I'm totally stuck. I drew the Free Body Diagram, but i have no idea where to go from there.
 
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Well what is the force parallel to the slope and what is the force normal to the slope?
 
i wasnt given any of that information, the only other thing i know is that Fn=-Fg, since there is no accel, so the Ffr= (9.81)μm... but where do i go from there?
 
Carriebun said:
i wasnt given any of that information, the only other thing i know is that Fn=-Fg, since there is no accel, so the Ffr= (9.81)μm... but where do i go from there?

You need to split the weight into two components, one parallel to the slope and one normal to it.

The one normal to it will be your normal force which will give you the frictional force.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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