Finding coefficient of friction given slope

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Homework Help Overview

The problem involves determining the coefficient of kinetic friction for a skier coasting down a slope at a constant speed. The slope is given as 3.5 degrees, and the discussion revolves around the forces acting on the skier.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the skier, including the normal force and the force of friction. Questions are raised about how to resolve the weight into components and how to apply the given information to find the coefficient of friction.

Discussion Status

The discussion is ongoing, with participants exploring the relationship between the forces involved. Some guidance has been offered regarding the need to split the weight into components, but there is no clear consensus on the next steps or the necessary information to proceed.

Contextual Notes

Participants note the lack of specific information about forces parallel and normal to the slope, which is essential for solving the problem. There is an emphasis on the absence of acceleration, which influences the forces at play.

Carriebun
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Homework Statement



A skier coasts down a 3.5 degree slope at a constant speed. Find the coefficient of kinetic friction between the skis and the snow covering the slope.


Homework Equations



coefficient of friction x Normal force = force friction

therefore: coefficeint of friction = force friction / normal force

The Attempt at a Solution



I'm totally stuck. I drew the Free Body Diagram, but i have no idea where to go from there.
 
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Well what is the force parallel to the slope and what is the force normal to the slope?
 
i wasnt given any of that information, the only other thing i know is that Fn=-Fg, since there is no accel, so the Ffr= (9.81)μm... but where do i go from there?
 
Carriebun said:
i wasnt given any of that information, the only other thing i know is that Fn=-Fg, since there is no accel, so the Ffr= (9.81)μm... but where do i go from there?

You need to split the weight into two components, one parallel to the slope and one normal to it.

The one normal to it will be your normal force which will give you the frictional force.
 

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