Finding complex solutions from an eqn.

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SUMMARY

The discussion centers on finding complex solutions to the equation z² + Conjugate(z²) = 0, specifically when z = 1 + i. Participants explore the implications of substituting z with 1 + i, leading to the equation (1 + i)² + Conjugate((1 + i)²) = 0. The correct interpretation reveals that the equation simplifies to 0, as (1 + i)² equals -1 + 2i, and its conjugate is -1 - 2i. Thus, the solutions hinge on understanding the properties of complex conjugates and their relationships.

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Given z = 1 + i,

Find all complex solutions to z^{2} + Conjugate:z^{2} = 0

I have come up with a way to solving this but it doesn't make any sense.

would it be:
z^{2} + 1-i = 0

z^{2} = -1+i

Solve for all complex roots

then do the same for conjugate squared?
 
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JC3187 said:
Given z = 1 + i,

Find all complex solutions to z^{2} + Conjugate:z^{2} = 0

I have come up with a way to solving this but it doesn't make any sense.

would it be:
z^{2} + 1-i = 0

z^{2} = -1+i

Solve for all complex roots

then do the same for conjugate squared?

Finding all complex solutions to z^2+conjugate(z^2)=0 makes a bit of sense. Adding "when z=1+i" makes it make no sense unless you just want to show (1+i)^2+(1-i)^2=0. Or do you just want to solve (1+i)^2+conjugate(z^2)=0??
 
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