Finding Components, Projections of 3D Vectors

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Homework Help Overview

The discussion revolves around finding components and projections of 3D vectors, specifically focusing on two vectors "a" and "b". The original poster seeks guidance on how to approach the problem, which involves calculating the component of "b" along "a", the projection of "b" onto "a", and the projection of "b" orthogonal to "a".

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relevance of dot products in solving the problem. The original poster expresses uncertainty about the complexity of the calculations involved. Another participant suggests visualizing the vectors and using geometric interpretations to understand the projections better.

Discussion Status

The discussion is ongoing, with participants exploring different methods and interpretations of the problem. Some guidance has been offered regarding the use of geometric representations and dot products, but no consensus or complete solutions have been reached.

Contextual Notes

The original poster notes that the topic has not been covered in class, indicating a potential gap in foundational knowledge that may affect their understanding of the problem.

somebodyelse5
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I won't post the actual problem with numbers, I just need some direction. My teacher never went over this part of the webwork in class, and we haven't touched on it in physics either.

"a" and "b" are both 3D vectors.

1.) I am supposed to find the component of "b" along "a"

2.) I am supposed to find the projection of "b" onto "a"

3.) I am supposed to find the projection of "b" orthogonal to "a"


If somewhat could shed some light on what I am actually doing, and maybe give me some direction it would be greatly appreciated.
 
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do you know about dot products? they could be pretty useful here...
 
lanedance said:
do you know about dot products? they could be pretty useful here...

yes, i know how to find dot and cross products. But its not as simple as just finding the dot product is it?
 
Draw a and b with their tails together. Drop a perpendicular from the head of a to the line of vector b forming a right triangle. The component on b of a is the "shadow" of a on b which is the b leg of that triangle and you can see from the picture its length is |b|cos(θ) where θ is the angle between a and b.

Notice that if you make a unit vector out of b, call it bhat that

[tex]|a|\cos\theta = |a||\hat b|\cos\theta = a\cdot \hat b[/tex]

If you multiply that by the unit vector bhat that makes a vector out of the "shadow" and that gives the projection of a on b. Subtracting that projection from a gives the vector forming the other leg of the triangle and that is the orthogonal projection.
 

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