Finding constant velocity,final velocity and acceleration of these cars?

[xod_s]

Homework Statement

Two cars go the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest and maintains a constant acceleration. Both cars cover a distance of 517 m in 215 and are moving in the + direction. Whats the constant velocity of car A as well as the final velocity and acceleration of car B?

Homework Equations

The Attempt at a Solution

 

[PeterO]

Homework Statement

Two cars go the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest and maintains a constant acceleration. Both cars cover a distance of 517 m in 215 and are moving in the + direction. Whats the constant velocity of car A as well as the final velocity and acceleration of car B?

Homework Equations

The Attempt at a Solution

Did you by any chance mean 21 s [seconds] rather than 215 and no units.

 

[xod_s]

@ PeterO "Did you by any chance mean 21 s [seconds] rather than 215 and no units."
Yes I did.Thank you for pointing that out.It's supoose to be 21 seconds not vaugely 215.Also if it helps I know for sure that the constant velocity of Car A is 2.40 m/s.

 

[PeterO]

@ PeterO "Did you by any chance mean 21 s [seconds] rather than 215 and no units."
Yes I did.Thank you for pointing that out.It's supoose to be 21 seconds not vaugely 215.Also if it helps I know for sure that the constant velocity of Car A is 2.40 m/s.

I hope you really meant 24.6 for the constant velocity.

One of the useful formulae for motion under constant acceleration is

s = (u + v)/2 .t

s = displacement, u = initial velocity, v = final velocity, t = time.

for acceleration zero, u = v so the (u + v)/2 = (v + v)/2 = v

The formula becomes s = vt, which you use to get that 24.6

when an object starts from rest, u = zero, so the formula becomes s = v/2 . t

from that you can get the final velocity.

as for acceleration .. the car reaches that velocity in 21 seconds, so you can divide by 21 to find the acceleration.