Finding critical numbers of trig function

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Homework Help Overview

The discussion revolves around finding the critical numbers of the function f(θ) = 2cosθ + sin²θ, with a focus on the differentiation process and the conditions under which the derivative equals zero.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the differentiation of the function and the resulting expression -2sinθ(1 - cosθ). Questions arise regarding the critical values derived from this expression and the conditions under which it equals zero.

Discussion Status

There is an ongoing exploration of the critical numbers, with participants correcting each other on the values of θ that satisfy the conditions of the sine and cosine functions. Some participants have offered clarifications about periodicity and the implications for critical values.

Contextual Notes

Participants are examining the periodic nature of sine and cosine functions, questioning the implications of their periodicity on the critical numbers. There is also a focus on the correct terminology regarding the mathematical constant π versus the word "pie."

TsAmE
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Homework Statement



Find the critical numbers of the function:

f(θ) = 2cosθ + sin^(2) θ

Homework Equations



None

The Attempt at a Solution



I differentiated the equation and got -2sinθ(1 - cosθ) and found the critical values to be θ = 0 degrees + 2pie * n but the correct answer was npie. Why is this?
 
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When is -2sinθ(1 - cosθ) equal to zero according to you? (check again I mean)
 
cosθ = 1 when x = 0 + 2npie, n E Z
-2sinθ = 0 when x = 0 + 2npie, n E Z
 
Edit: Corrected an error I made.
cosθ = 1 for x = n*2pi
sinθ = 0 for x = ..., -2pi, - pi, 0, pi, 2pi, 3pi, ...
 
Last edited:
No Mark! cosθ = 1 for θ = n*2pi, so you are correct TsAmE.
but you indeed made an error with the sinus:

sin(x)= 0 for x = n*pi
 
justsof said:
sin(x)= 0 for x = n*pi

Why does sinx have the same value every pie (180 degrees)? Doesnt it only repeat every 2pie since it is its period?
 
justsof said:
No Mark! cosθ = 1 for θ = n*2pi, so you are correct TsAmE.
Right. I don't know what I was thinking. I have edited my earlier reply.
justsof said:
but you indeed made an error with the sinus:

sin(x)= 0 for x = n*pi
 
TsAmE said:
Why does sinx have the same value every pie (180 degrees)? Doesnt it only repeat every 2pie since it is its period?
The graphs of y = cosx and y = sinx are periodic with period 2pi, but both cross the horizontal axis at multiples of pi. But that doesn't mean that the period of each is pi. For periodicity, f(x + p) = f(x) for all x, not just a select few values.
 
Mark44 said:
The graphs of y = cosx and y = sinx are periodic with period 2pi, but both cross the horizontal axis at multiples of pi. But that doesn't mean that the period of each is pi. For periodicity, f(x + p) = f(x) for all x, not just a select few values.

What do you mean by f(x + p) = f(x) and what is your f(x). What if my critical number was t = pie/6 OR t = -pie/2, would the critical values be at pie/6 + npie OR t = -pie/2 + npie?
 
Last edited:
  • #10
That's the definition of periodicity. If a function f satisfies f(x + p) = f(x) for all x, f is periodic with period p.

The cosine and sine functions are periodic with period 2pi. BTW, pie is something you eat. Pi is the name of the Greek letter [itex]\pi[/itex]. If you want to appear intelligent, don't write pie when you mean pi.

If your critical number was t = pi/6 for the cosine or sine function, then pi/6 + n(2pi) would also be a critical number.
 
  • #11
Mark44 said:
That's the definition of periodicity. If a function f satisfies f(x + p) = f(x) for all x, f is periodic with period p.

The cosine and sine functions are periodic with period 2pi. BTW, pie is something you eat. Pi is the name of the Greek letter [itex]\pi[/itex]. If you want to appear intelligent, don't write pie when you mean pi.

If your critical number was t = pi/6 for the cosine or sine function, then pi/6 + n(2pi) would also be a critical number.

Lol I didnt even notice that I wrote pie. So the only time that you add "n(pi)" to the period is when sinx or cosx = 0, and for any other values you would instead add "2n(pi)"?
 
  • #13
Are there any other special cases where you wouldn't say "+ 2n(pi)"?
 
  • #14
No, not for the sine and cosine functions.
 

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