Finding current in a complex circuit with resistors

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Homework Help Overview

The discussion revolves around analyzing a complex circuit with resistors to determine the current through the battery. Participants express confusion regarding the identification of resistors in series and parallel configurations, which is crucial for calculating the equivalent resistance.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to identify series and parallel resistors to calculate the equivalent resistance (R_eq). Some suggest using Kirchhoff's rules for a comprehensive analysis, while others mention the node-voltage method and a star-delta transformation as potential approaches.

Discussion Status

The discussion includes various interpretations of the circuit's configuration. While some participants have proposed specific methods for analysis, there is no explicit consensus on the best approach, and confusion remains regarding the circuit layout.

Contextual Notes

Participants note that the circuit's layout complicates the identification of series and parallel resistors, leading to differing opinions on how to proceed with the analysis.

Goomba
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I am given the following circuit:
yf_Figure_26_53.jpg


How do I find the current through the battery? I have trouble seeing which resistors are in series and which resistors are in parallel. I think I need to figure that out and then calculate R_eq accordingly. Then set I=V/R and solve for I.

But which resistors are in series and which are in parallel? It's confusing the way the circuit is laid out here...
 
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Use conservation of charge (KCL) at the two nodes across R3.
 
Goomba said:
I am given the following circuit:
yf_Figure_26_53.jpg


How do I find the current through the battery? I have trouble seeing which resistors are in series and which resistors are in parallel. I think I need to figure that out and then calculate R_eq accordingly. Then set I=V/R and solve for I.

But which resistors are in series and which are in parallel? It's confusing the way the circuit is laid out here...

No two resistors are in series nor in parallel here. There is no way to simplify. You must solve the entire circuit using Kirchhoff's rules. Find the current flowing out of the battery (no need to find the other currents). Then just use R_eq = V_battery / I_ out of the battery.

Pat
 
Thanks

I figured it out. :biggrin: The node-voltage method is a beautiful thing.
 
u can also use the star-delta transformation to simplify the circuit given
 

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