Finding Current in a Long Solenoid

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SUMMARY

The discussion focuses on calculating the current in a long solenoid with 100 turns/cm, where an electron moves in a circular path of radius 2.20 cm at a speed of 0.048c. The formula used for the calculation is i = mv/e*μ*n*r. The correct current calculated is 0.297 A, as opposed to the initial incorrect calculation of 0.266 A, which was attributed to a typo and improper use of brackets in the denominator.

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Homework Statement


A long solenoid has 100 turns/cm and carries current i. An electron moves within the solenoid in a circle of radius 2.20 cm perpendicular to the solenoid axis. The speed of the electron is 0.048 c (c = speed of light). Find the current i in the solenoid.



Homework Equations



i= mv/e*mu*n*r

The Attempt at a Solution


i= (9.11E-31kg)(.0480)(3.0E8)/ (1.6E-10 C)(4*pi E-7 Tm/A)(100/.01 m) (2.2E-2) = .266 A
this answer is wrong...
what am i doing wrong? thank you!
 
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Probably a typo but you wrote 1.6E-10 for the charge on the electron.
Of course you need brackets around all the factors in the denominator.
I ran your calc through my calculator and got .297 A.
 
yeah, that's right! i must have messed up on the calculations somewhere!
 

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